Implement proposal in #212 (closed): add error if GraphView::replace() is used with two sets for the following conditions:
Inputs conditions:
| old \ new | 1 node, 1 input | >1 node, 1 input | 1 node, >1 inputs | >1 node, >1 inputs |
|---|---|---|---|---|
| 1 node, 1 input | trivial | trivial | broadcast | broadcast |
| >1 node, 1 input | trivial | trivial | broadcast | broadcast |
| 1 node, >1 inputs | (take first) | (take first) | same order | X |
| >1 node, >1 inputs | X | X | X | X |
Outputs conditions:
| old \ new | 1 node, 1 output | >1 node, 1 output | 1 node, >1 outputs | >1 node, >1 outputs |
|---|---|---|---|---|
| 1 node, 1 output | trivial | trivial | take first | X |
| >1 node, 1 output | trivial | trivial | take first | X |
| 1 node, >1 outputs | (take first) | (take first) | same order | X |
| >1 node, >1 outputs | X | X | X | X |
Only the X cases cannot possibly be resolved deterministically with sets of node.
These cases are therefore forbidden for the set-based replace() interface.
The remaining cases are handled by the GraphView-based replace() interface.
If they are not supported, the function returns false.
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