Commit 3d006566 authored by Jeno Attila Balasko's avatar Jeno Attila Balasko Committed by Gerrit Code Review
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Merge "Made certain function tests less strict when matching float values...

Merge "Made certain function tests less strict when matching float values after float display change"
parents 77bdf234 465c48ec
......@@ -1865,7 +1865,7 @@ const ftype4 f8 := f7;
(?im)not.+?valid.+?value.+?for.+?subtype
<END_RESULT>
<RESULT COUNT 1>
(?is)\berror: Subtype mismatch: subtype \(6(\.0)?e0\.\.7(\.0)?e0\) has no common value with subtype \(4\.1e-1,1(\.0)?e0,2(\.0)?e0,8.0e0\.\.1(\.0)?e1\)
(?is)\berror: Subtype mismatch: subtype \(6(\.0)?e0\.\.7(\.0)?e0\) has no common value with subtype \(4\..*e-1,1(\.0)?e0,2(\.0)?e0,8.0e0\.\.1(\.0)?e1\)
<END_RESULT>
<RESULT COUNT 4>
(?is)\berror:
......
......@@ -5571,13 +5571,13 @@ module module1
(?is)\berror: 4.0e0 is not a valid value for type `float' which has subtype \(1.0e0,2.0e0,3.0e0\)
<END_RESULT>
<RESULT COUNT 1>
(?is)\berror: The subtype restriction is not a subset of the restriction on the parent type. Subtype \(4.0e0\) is not subset of subtype \(1.0e0,2.0e0,3.0e0\)
(?is)\berror: The subtype restriction is not a subset of the restriction on the parent type. Subtype \(4.*e0\) is not subset of subtype \(1.0e0,2.0e0,3.0e0\)
<END_RESULT>
<RESULT COUNT 1>
(?is)\berror: The subtype restriction is not a subset of the restriction on the parent type. Subtype \(4.0e0..8.0e0\) is not subset of subtype \(1.0e0,2.0e0,3.0e0\)
(?is)\berror: The subtype restriction is not a subset of the restriction on the parent type. Subtype \(4.*e0..8.0e0\) is not subset of subtype \(1.0e0,2.0e0,3.0e0\)
<END_RESULT>
<RESULT COUNT 1>
(?is)\berror: The subtype restriction is not a subset of the restriction on the parent type. Subtype \(4.0e0..8.0e0,1.6e1\) is not subset of subtype \(1.0e0,2.0e0,3.0e0\)
(?is)\berror: The subtype restriction is not a subset of the restriction on the parent type. Subtype \(4.*e0..8.0e0,1.6.*e1\) is not subset of subtype \(1.0e0,2.0e0,3.0e0\)
<END_RESULT>
<RESULT COUNT 11>
(?is)\berror:
......
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